If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
(1/5)*(12*x-10) = 0
1/5*(12*x-10) = 0
( 1/5 )
1/5 = 0
x belongs to the empty set
( 12*x-10 )
12*x-10 = 0 // + 10
12*x = 10 // : 12
x = 10/12
x = 5/6
x = 5/6
| 22x+14x-6=60x+3 | | 27=9-x+5 | | 2/5(6x-1) | | 3(7x-19)-19x=-15 | | 8b^2-8b=-2 | | 8-x+3=16 | | p^2+6p=-8 | | 4-2(-6-3c)= | | 42=2m-10 | | 125=25x+5 | | x/5=9=4 | | 2x+5x-3y+-2+8= | | 22X+17x-6=60x+3 | | f(x)=-1/2x^2 | | 14-3e=25-3e | | 14-3e=25-e | | -6q-0.4(20+15q)=16 | | 15=-b-5 | | (2x-113)+(x+25)=180 | | 43+-3x=139 | | 4x^2-10+1=0 | | f(x)=-1/2x2 | | 6b^2-11b-2=0 | | 2z+2=2.4 | | 2(4x+1)=-2(-2x-1)+4x | | 12/5x-2 | | 6-3x=12-3x | | 3/5x=14 | | 8x-10+6x+10x+10=360 | | -8(3d-2)+4d= | | -3(2x-5)=3(x-1) | | 2x^2+6x^3+5x^7+15x^8=0 |