1/5(14x-23)=2/3(12x-7)

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Solution for 1/5(14x-23)=2/3(12x-7) equation: 



1/5(14x-23)=2/3(12x-7)

We move all terms to the left:

1/5(14x-23)-(2/3(12x-7))=0



Domain of the equation: 5(14x-23)!=0

x∈R





Domain of the equation: 3(12x-7))!=0

x∈R



We calculate fractions


(3x1/(5(14x-23)*3(12x-7)))+(-10x1/(5(14x-23)*3(12x-7)))=0



We calculate terms in parentheses: +(3x1/(5(14x-23)*3(12x-7))), so:

3x1/(5(14x-23)*3(12x-7))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-10x1/(5(14x-23)*3(12x-7))), so:

-10x1/(5(14x-23)*3(12x-7))

We multiply all the terms by the denominator


-10x1

We add all the numbers together, and all the variables

-10x

Back to the equation:

+(-10x)



We get rid of parentheses

3x-10x=0

We add all the numbers together, and all the variables

-7x=0

x=0/-7

x=0

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