1/5(15j-25)=2/3(11-15)

Simple and best practice solution for 1/5(15j-25)=2/3(11-15) equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 1/5(15j-25)=2/3(11-15) equation:


j in (-oo:+oo)

(1/5)*(15*j-25) = (2/3)*(11-15) // - (2/3)*(11-15)

(1/5)*(15*j-25)-((2/3)*(11-15)) = 0

(1/5)*(15*j-25)+(-2/3)*(11-15) = 0

1/5*(15*j-25)+8/3 = 0

(1/5*3*(15*j-25))/3+8/3 = 0

1/5*3*(15*j-25)+8 = 0

9*j-7 = 0

(9*j-7)/3 = 0

(9*j-7)/3 = 0 // * 3

9*j-7 = 0

9*j-7 = 0 // + 7

9*j = 7 // : 9

j = 7/9

j = 7/9

See similar equations:

| 4.2x=-36.54 | | y=(2-3)squared | | 6(7x+5)=198 | | 2/x-2/1-x/x | | 45y+15= | | y=(1-3)squared | | 20+0.5y=x | | 3/10=a/14 | | k-5=25 | | 6(4x+2)=276 | | y=(0-3)squared | | 7a+2-b=2a+b | | y=(-1-3)squared | | 2(a-b)+5(a+b)=13 | | 1.05-x=0 | | 28.72+0.31x=40 | | 3x+5*4x=4 | | 2*abs(z-3i)=abs(z+3i) | | 7(1-8)+24=x(1-6) | | 27b^2-b=0 | | 3x+5*4x=5 | | 2=-5+v | | 4k/3=8,k= | | V(x)=5.2x+340 | | y=(-2-3)squared | | V(x)=5.2x+350 | | Y=-2t^2+8t+4 | | 35/k=7 | | u=3(1)+7 | | y=(0-3)sqaured | | 192+-3z=555 | | -6=v+5 |

Equations solver categories