1/5(15x+45)-17=-1/2(10x-6)

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Solution for 1/5(15x+45)-17=-1/2(10x-6) equation:



1/5(15x+45)-17=-1/2(10x-6)
We move all terms to the left:
1/5(15x+45)-17-(-1/2(10x-6))=0
Domain of the equation: 5(15x+45)!=0
x∈R
Domain of the equation: 2(10x-6))!=0
x∈R
We calculate fractions
(2x1/(5(15x+45)*2(10x-6)))+(-(-5x1)/(5(15x+45)*2(10x-6)))-17=0
We calculate terms in parentheses: +(2x1/(5(15x+45)*2(10x-6))), so:
2x1/(5(15x+45)*2(10x-6))
We multiply all the terms by the denominator
2x1
We add all the numbers together, and all the variables
2x
Back to the equation:
+(2x)
We calculate terms in parentheses: +(-(-5x1)/(5(15x+45)*2(10x-6))), so:
-(-5x1)/(5(15x+45)*2(10x-6))
We add all the numbers together, and all the variables
-(-5x)/(5(15x+45)*2(10x-6))
We multiply all the terms by the denominator
-(-5x)
We get rid of parentheses
5x
Back to the equation:
+(5x)
We add all the numbers together, and all the variables
7x-17=0
We move all terms containing x to the left, all other terms to the right
7x=17
x=17/7
x=2+3/7

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