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1/5(15x-)=2x+9
We move all terms to the left:
1/5(15x-)-(2x+9)=0
Domain of the equation: 5(15x-)!=0We add all the numbers together, and all the variables
x∈R
1/5(+15x)-(2x+9)=0
We get rid of parentheses
1/5(+15x)-2x-9=0
We multiply all the terms by the denominator
-2x*5(+15x)-9*5(+15x)+1=0
Wy multiply elements
-10x^2(+-45x(++1=0
We use the square of the difference formula
-10x^2(-45x(+1=0
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