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1/5(15x-40)=x-16
We move all terms to the left:
1/5(15x-40)-(x-16)=0
Domain of the equation: 5(15x-40)!=0We get rid of parentheses
x∈R
1/5(15x-40)-x+16=0
We multiply all the terms by the denominator
-x*5(15x-40)+16*5(15x-40)+1=0
Wy multiply elements
-5x^2(1+80x(1+1=0
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