If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/5(2(x-1)+20)=x
We move all terms to the left:
1/5(2(x-1)+20)-(x)=0
Domain of the equation: 5(2(x-1)+20)!=0We add all the numbers together, and all the variables
x∈R
-1x+1/5(2(x-1)+20)=0
We multiply all the terms by the denominator
-1x*5(2(x-1)+20)+1=0
Wy multiply elements
-5x^2(2+1=0
| 7x-7=44+6x | | 110+0.6m=50+0.7m | | |8+9x|=53 | | 7x=2=2 | | x⁴+15x²-16=0 | | 7=2/n | | -7(7-6p)+8=35+4p | | 4.3x=x+6 | | -6=-36+6a | | 4u-6=-4 | | 1/2(6x-10)=22 | | 5y-36-4(3-2y=) | | -3=r/6 | | 1/2(12x-10)=31 | | 3(9-a)=2(a+3)+16a | | 21=41+7x | | 2(2x+3)-15=39 | | 10-x=31 | | -12x=7=-5 | | 3.2x+2=8 | | -48y=-96 | | 3+10/x=2(x+5)/x | | x/15+3=5 | | 19z=57 | | 7–4x=–21 | | 8/2=n/4 | | 2(x=2)=2 | | 2.x-3=7 | | 6y=7y+8 | | x-3x+4=-6 | | p-(-8)=0 | | 3(2n+0.2)=0.6 |