1/5(2-7k)=-2(4K+3)

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Solution for 1/5(2-7k)=-2(4K+3) equation:



1/5(2-7k)=-2(4+3)
We move all terms to the left:
1/5(2-7k)-(-2(4+3))=0
Domain of the equation: 5(2-7k)!=0
k∈R
We add all the numbers together, and all the variables
1/5(-7k+2)-(-27)=0
We add all the numbers together, and all the variables
1/5(-7k+2)+27=0
We multiply all the terms by the denominator
27*5(-7k+2)+1=0
Wy multiply elements
135k(-+1=0
We use the square of the difference formula
135k(-1=0

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