1/5(2-7k)=-2(4K+3)

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Solution for 1/5(2-7k)=-2(4K+3) equation: 



1/5(2-7k)=-2(4+3)

We move all terms to the left:

1/5(2-7k)-(-2(4+3))=0



Domain of the equation: 5(2-7k)!=0

k∈R



We add all the numbers together, and all the variables

1/5(-7k+2)-(-27)=0

We add all the numbers together, and all the variables

1/5(-7k+2)+27=0

We multiply all the terms by the denominator


27*5(-7k+2)+1=0

Wy multiply elements

135k(-+1=0

We use the square of the difference formula

135k(-1=0

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