1/5(20x+5)-9=-1/2(6x-8)

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Solution for 1/5(20x+5)-9=-1/2(6x-8) equation: 



1/5(20x+5)-9=-1/2(6x-8)

We move all terms to the left:

1/5(20x+5)-9-(-1/2(6x-8))=0



Domain of the equation: 5(20x+5)!=0

x∈R





Domain of the equation: 2(6x-8))!=0

x∈R



We calculate fractions


(2x6/(5(20x+5)*2(6x-8)))+(-(-5x2)/(5(20x+5)*2(6x-8)))-9=0



We calculate terms in parentheses: +(2x6/(5(20x+5)*2(6x-8))), so:

2x6/(5(20x+5)*2(6x-8))

We multiply all the terms by the denominator


2x6

We add all the numbers together, and all the variables

2x^6

We do not support expression: x^6

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