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1/5(25+15x)-x=2(x+3)-1
We move all terms to the left:
1/5(25+15x)-x-(2(x+3)-1)=0
Domain of the equation: 5(25+15x)!=0We add all the numbers together, and all the variables
x∈R
1/5(15x+25)-x-(2(x+3)-1)=0
We add all the numbers together, and all the variables
-1x+1/5(15x+25)-(2(x+3)-1)=0
We multiply all the terms by the denominator
-1x*5(15x+25)-((2(x+3)-1))*5(15x+25)+1=0
We calculate terms in parentheses: -((2(x+3)-1))*5(15x+25), so:Wy multiply elements
(2(x+3)-1))*5(15x+25
-5x^2(1-((2(x+3)-1))*5(15x+25)+1=0
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