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1/5(25-10b)+4=1/3(9b-15)-6
We move all terms to the left:
1/5(25-10b)+4-(1/3(9b-15)-6)=0
Domain of the equation: 5(25-10b)!=0
b∈R
Domain of the equation: 3(9b-15)-6)!=0We add all the numbers together, and all the variables
b∈R
1/5(-10b+25)-(1/3(9b-15)-6)+4=0
We calculate fractions
(3b9/(5(-10b+25)*3(9b-15))+(-5b0/(5(-10b+25)*3(9b-15))+4=0
We can not solve this equation
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