1/5(25-10b)+6=1/3(9b-15)-9

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Solution for 1/5(25-10b)+6=1/3(9b-15)-9 equation: 



1/5(25-10b)+6=1/3(9b-15)-9

We move all terms to the left:

1/5(25-10b)+6-(1/3(9b-15)-9)=0



Domain of the equation: 5(25-10b)!=0

b∈R





Domain of the equation: 3(9b-15)-9)!=0

b∈R



We add all the numbers together, and all the variables

1/5(-10b+25)-(1/3(9b-15)-9)+6=0

We calculate fractions


(3b9/(5(-10b+25)*3(9b-15))+(-5b0/(5(-10b+25)*3(9b-15))+6=0

We can not solve this equation

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