1/5(25-5a)-4-a=0

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Solution for 1/5(25-5a)-4-a=0 equation: 



1/5(25-5a)-4-a=0



Domain of the equation: 5(25-5a)!=0

a∈R



We add all the numbers together, and all the variables

1/5(-5a+25)-a-4=0

We add all the numbers together, and all the variables

-1a+1/5(-5a+25)-4=0

We multiply all the terms by the denominator


-1a*5(-5a+25)-4*5(-5a+25)+1=0

Wy multiply elements

-5a^2(--20a(-+1=0

We use the square of the difference formula

-5a^2(+20a(-1=0

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