1/5(25-5a)=(4-a)

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Solution for 1/5(25-5a)=(4-a) equation: 



1/5(25-5a)=(4-a)

We move all terms to the left:

1/5(25-5a)-((4-a))=0



Domain of the equation: 5(25-5a)!=0

a∈R



We add all the numbers together, and all the variables

1/5(-5a+25)-((-1a+4))=0

We multiply all the terms by the denominator


-(((-1a+4)))*5(-5a+25)+1=0



We calculate terms in parentheses: -(((-1a+4)))*5(-5a+25), so:

((-1a+4)))*5(-5a+25

We add all the numbers together, and all the variables

-5a+((-1a+4)))*5(+25

Back to the equation:

-(-5a+((-1a+4)))*5(+25)



We add all the numbers together, and all the variables

-(-5a+((-1a+4)))*525+1=0

We move all terms containing a to the left, all other terms to the right

-(-5a+((-1a+4)))*525=-1

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