1/5(25-5a)=4-4a

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Solution for 1/5(25-5a)=4-4a equation:



1/5(25-5a)=4-4a
We move all terms to the left:
1/5(25-5a)-(4-4a)=0
Domain of the equation: 5(25-5a)!=0
a∈R
We add all the numbers together, and all the variables
1/5(-5a+25)-(-4a+4)=0
We get rid of parentheses
1/5(-5a+25)+4a-4=0
We multiply all the terms by the denominator
4a*5(-5a+25)-4*5(-5a+25)+1=0
Wy multiply elements
20a^2(--20a(-+1=0
We use the square of the difference formula
20a^2(+20a(-1=0

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