1/5(25-5k)=21-3(1k-4)

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Solution for 1/5(25-5k)=21-3(1k-4) equation: 



1/5(25-5k)=21-3(1k-4)

We move all terms to the left:

1/5(25-5k)-(21-3(1k-4))=0



Domain of the equation: 5(25-5k)!=0

k∈R



We add all the numbers together, and all the variables

1/5(-5k+25)-(21-3(k-4))=0

We multiply all the terms by the denominator


-((21-3(k-4)))*5(-5k+25)+1=0



We calculate terms in parentheses: -((21-3(k-4)))*5(-5k+25), so:

(21-3(k-4)))*5(-5k+25

We add all the numbers together, and all the variables

-5k+(21-3(k-4)))*5(+25

Back to the equation:

-(-5k+(21-3(k-4)))*5(+25)



We add all the numbers together, and all the variables

-(-5k+(21-3(k-4)))*525+1=0

We move all terms containing k to the left, all other terms to the right

-(-5k+(21-3(k-4)))*525=-1

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