1/5(25-5k)=21-3(K-4)

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Solution for 1/5(25-5k)=21-3(K-4) equation: 


x in (-oo:+oo)

(1/5)*(25-(5*k)) = 21-(3*(K-4)) // - 21-(3*(K-4))

(1/5)*(25-(5*k))+3*(K-4)-21 = 0

(1/5)*(25-5*k)+3*(K-4)-21 = 0

1/5*(25-5*k)+3*(K-4)-21 = 0

1/5*(25-5*k)+3*(K-4)-21 = 0

3*K-k-21-7 = 0

3*K-k-28 = 0

3*K-k-28 = 0

x belongs to the empty set

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