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x in (-oo:+oo)
(1/5)*(25-(5*x)) = 4-x // - 4-x
(1/5)*(25-(5*x))+x-4 = 0
(1/5)*(25-5*x)+x-4 = 0
1/5*(25-5*x)+x-4 = 0
1/5*(25-5*x)+x-4 = 0
5-4 = 0
1 = 0
1 = 0
1 = 0
x belongs to the empty set
x belongs to the empty set
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