1/5(25x+20)-10=1/2(4x-4)

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Solution for 1/5(25x+20)-10=1/2(4x-4) equation: 



1/5(25x+20)-10=1/2(4x-4)

We move all terms to the left:

1/5(25x+20)-10-(1/2(4x-4))=0



Domain of the equation: 5(25x+20)!=0

x∈R





Domain of the equation: 2(4x-4))!=0

x∈R



We calculate fractions


(2x4/(5(25x+20)*2(4x-4)))+(-5x2/(5(25x+20)*2(4x-4)))-10=0



We calculate terms in parentheses: +(2x4/(5(25x+20)*2(4x-4))), so:

2x4/(5(25x+20)*2(4x-4))

We multiply all the terms by the denominator


2x4

We add all the numbers together, and all the variables

2x^4

We do not support expression: x^4

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