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1/5(25x+40)=5x+32
We move all terms to the left:
1/5(25x+40)-(5x+32)=0
Domain of the equation: 5(25x+40)!=0We get rid of parentheses
x∈R
1/5(25x+40)-5x-32=0
We multiply all the terms by the denominator
-5x*5(25x+40)-32*5(25x+40)+1=0
Wy multiply elements
-25x^2(2-160x(2+1=0
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