1/5(25x-75)+9=1/4(8x=36)

Solution for 1/5(25x-75)+9=1/4(8x=36) equation:

1/5(25x-75)+9=1/4(8x=36)

We move all terms to the left:

1/5(25x-75)+9-(1/4(8x)=0


Domain of the equation: 5(25x-75)!=0

x∈R



Domain of the equation: 48x+9!=0

We move all terms containing x to the left, all other terms to the right

48x!=-9

x!=-9/48

x!=-3/16

x∈R


We calculate fractions


(48x+9)/(6000x^2-18000x+9)+(-5x2/(6000x^2-18000x+9)=0


We calculate terms in parentheses: +(-5x2/(6000x^2-18000x+9), so:

-5x2/(6000x^2-18000x+9

We multiply all the terms by the denominator


-5x2

We add all the numbers together, and all the variables

-5x^2

Back to the equation:

+(-5x^2)


We get rid of parentheses

-5x^2+(48x+9)/(6000x^2-18000x+9)=0

We multiply all the terms by the denominator


-5x^2*(6000x^2-18000x+9)+(48x+9)=0

We get rid of parentheses

-5x^2*(6000x^2-18000x+9)+48x+9=0

We move all terms containing x to the left, all other terms to the right

-5x^2*(6000x^2-18000x+9)+48x=-9