1/5(25x-75)-4=1/2(2x+54)

Solution for 1/5(25x-75)-4=1/2(2x+54) equation:

1/5(25x-75)-4=1/2(2x+54)

We move all terms to the left:

1/5(25x-75)-4-(1/2(2x+54))=0


Domain of the equation: 5(25x-75)!=0

x∈R



Domain of the equation: 2(2x+54))!=0

x∈R


We calculate fractions


(2x2/(5(25x-75)*2(2x+54)))+(-5x2/(5(25x-75)*2(2x+54)))-4=0


We calculate terms in parentheses: +(2x2/(5(25x-75)*2(2x+54))), so:

2x2/(5(25x-75)*2(2x+54))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)



We calculate terms in parentheses: +(-5x2/(5(25x-75)*2(2x+54))), so:

-5x2/(5(25x-75)*2(2x+54))

We multiply all the terms by the denominator


-5x2

We add all the numbers together, and all the variables

-5x^2

Back to the equation:

+(-5x^2)


We add all the numbers together, and all the variables

2x^2+(-5x^2)-4=0

We get rid of parentheses

2x^2-5x^2-4=0

We add all the numbers together, and all the variables

-3x^2-4=0

a = -3; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-3)·(-4)
Δ = -48
Delta is less than zero, so there is no solution for the equation