1/5(26-5a)=4-a

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Solution for 1/5(26-5a)=4-a equation: 



1/5(26-5a)=4-a

We move all terms to the left:

1/5(26-5a)-(4-a)=0



Domain of the equation: 5(26-5a)!=0

a∈R



We add all the numbers together, and all the variables

1/5(-5a+26)-(-1a+4)=0

We get rid of parentheses

1/5(-5a+26)+1a-4=0

We multiply all the terms by the denominator


1a*5(-5a+26)-4*5(-5a+26)+1=0

Wy multiply elements

5a^2(--20a(-+1=0

We use the square of the difference formula

5a^2(+20a(-1=0

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