If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/5(285-10x)=x
We move all terms to the left:
1/5(285-10x)-(x)=0
Domain of the equation: 5(285-10x)!=0We add all the numbers together, and all the variables
x∈R
1/5(-10x+285)-x=0
We add all the numbers together, and all the variables
-1x+1/5(-10x+285)=0
We multiply all the terms by the denominator
-1x*5(-10x+285)+1=0
Wy multiply elements
-5x^2(-+1=0
We use the square of the difference formula
-5x^2(-1=0
| 23j=874 | | 325-75=(x-200)x.25x | | 70+30x=2500 | | c/28=31 | | 4g=152 | | 68.96=4c+5 | | X=1/5(285-10x | | (8x-5)=(6x+3) | | 18k=396 | | 38.4=1/2b12.8 | | 4.0x10^11=(x)(0.075+x) | | A=1/2b12.8 | | 21=d/26 | | w/3=27 | | 17x-3=-37 | | −47p=–12 | | 56h=15 | | 23=g-9 | | x/9=11/18 | | 14q=6 | | y-55=45 | | 2(14)x-9=42 | | 2(14)x+12=21 | | 2(14)x-12=22 | | 10z-13=37 | | 2(14)x-21=53 | | 20+3u=89 | | 2(14)x+22=68 | | 24=v/4+21 | | 3(v-8)-7v=-4 | | 2(14)x+44=68 | | 2(14)x-42=70 |