1/5(2a-5)-4=1/2(a+4)=7/10

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Solution for 1/5(2a-5)-4=1/2(a+4)=7/10 equation:



1/5(2a-5)-4=1/2(a+4)=7/10
We move all terms to the left:
1/5(2a-5)-4-(1/2(a+4))=0
Domain of the equation: 5(2a-5)!=0
a∈R
Domain of the equation: 2(a+4))!=0
a∈R
We calculate fractions
(2aa/(5(2a-5)*2(a+4)))+(-5a2/(5(2a-5)*2(a+4)))-4=0
We calculate terms in parentheses: +(2aa/(5(2a-5)*2(a+4))), so:
2aa/(5(2a-5)*2(a+4))
We multiply all the terms by the denominator
2aa
Back to the equation:
+(2aa)
We calculate terms in parentheses: +(-5a2/(5(2a-5)*2(a+4))), so:
-5a2/(5(2a-5)*2(a+4))
We multiply all the terms by the denominator
-5a2
We add all the numbers together, and all the variables
-5a^2
Back to the equation:
+(-5a^2)
We get rid of parentheses
-5a^2+2aa-4=0
We move all terms containing a to the left, all other terms to the right
-5a^2+2aa=4

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