1/5(2f-3)+1/6(f-4)+2/15=0

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Solution for 1/5(2f-3)+1/6(f-4)+2/15=0 equation: 



1/5(2f-3)+1/6(f-4)+2/15=0



Domain of the equation: 5(2f-3)!=0

f∈R





Domain of the equation: 6(f-4)!=0

f∈R



We calculate fractions


(90ff/(5(2f-3)*6(f-4)*15)+(75f2/(5(2f-3)*6(f-4)*15)+(60f^22/(5(2f-3)*6(f-4)*15)=0



We calculate terms in parentheses: +(90ff/(5(2f-3)*6(f-4)*15)+(75f2/(5(2f-3)*6(f-4)*15)+(60f^22/(5(2f-3)*6(f-4)*15), so:

90ff/(5(2f-3)*6(f-4)*15)+(75f2/(5(2f-3)*6(f-4)*15)+(60f^22/(5(2f-3)*6(f-4)*15

We do not support efpression: f^22

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