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v in (-oo:+oo)
(1/5)*(2*v-3) = (2/5)*v-10 // - (2/5)*v-10
(1/5)*(2*v-3)-((2/5)*v)+10 = 0
(1/5)*(2*v-3)+(-2/5)*v+10 = 0
1/5*(2*v-3)+(-2*v)/5+10 = 0
(1/5*5*(2*v-3))/5+(-2*v)/5+(5*10)/5 = 0
1/5*5*(2*v-3)-2*v+5*10 = 0
50-3 = 0
47 = 0
47/5 = 0
47/5 = 0 // * 5
47 = 0
v belongs to the empty set
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