1/5(2x+3)+5=x-7

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Solution for 1/5(2x+3)+5=x-7 equation: 



1/5(2x+3)+5=x-7

We move all terms to the left:

1/5(2x+3)+5-(x-7)=0



Domain of the equation: 5(2x+3)!=0

x∈R



We get rid of parentheses

1/5(2x+3)-x+7+5=0

We multiply all the terms by the denominator


-x*5(2x+3)+7*5(2x+3)+5*5(2x+3)+1=0

Wy multiply elements

-5x^2(2+35x(2+25x(2+1=0

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