1/5(2x+3)+5=x-7

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Solution for 1/5(2x+3)+5=x-7 equation:



1/5(2x+3)+5=x-7
We move all terms to the left:
1/5(2x+3)+5-(x-7)=0
Domain of the equation: 5(2x+3)!=0
x∈R
We get rid of parentheses
1/5(2x+3)-x+7+5=0
We multiply all the terms by the denominator
-x*5(2x+3)+7*5(2x+3)+5*5(2x+3)+1=0
Wy multiply elements
-5x^2(2+35x(2+25x(2+1=0

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