1/5(2x+3)-3x=3/5-(2x+1)

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Solution for 1/5(2x+3)-3x=3/5-(2x+1) equation: 



1/5(2x+3)-3x=3/5-(2x+1)

We move all terms to the left:

1/5(2x+3)-3x-(3/5-(2x+1))=0



Domain of the equation: 5(2x+3)!=0

x∈R





Domain of the equation: 5-(2x+1))!=0

We move all terms containing x to the left, all other terms to the right

-(2x+1))!=-5

x∈R



We add all the numbers together, and all the variables

-3x+1/5(2x+3)-(3/5-(2x+1))=0

We calculate fractions


-3x+(-(2x+1))+1*5)/(50x-(2x+1))+75)+(-15x2/(50x-(2x+1))+75)=0



We calculate terms in parentheses: +(-(2x+1)), so:

-(2x+1)

We get rid of parentheses

-2x-1

Back to the equation:

+(-2x-1)



We get rid of parentheses

-3x-2x+1*5)/(50x-(2x+1))+75)+(-15x2/(50x-2x-1-1))+75=0

We multiply all the terms by the denominator


-3x*(50x-2x*(50x+1*5)-(2x+1))-15x2-2x*(50x-1*(50x-1)+75)*(50x+75)+(=0

We add all the numbers together, and all the variables

-3x*(50x-2x*(50x+5)-(2x+1))-15x2-2x*(50x-1*(50x-1)+75)*(50x+75)+(=0

We add all the numbers together, and all the variables

-15x^2-3x*(50x-2x*(50x+5)-(2x+1))-2x*(50x-1*(50x-1)+75)*(50x+75)=0

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