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1/5(2x-1)=7x-2
We move all terms to the left:
1/5(2x-1)-(7x-2)=0
Domain of the equation: 5(2x-1)!=0We get rid of parentheses
x∈R
1/5(2x-1)-7x+2=0
We multiply all the terms by the denominator
-7x*5(2x-1)+2*5(2x-1)+1=0
Wy multiply elements
-35x^2(2+10x(2+1=0
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