1/5(2y+4)=1/2(y-3)

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Solution for 1/5(2y+4)=1/2(y-3) equation:



1/5(2y+4)=1/2(y-3)
We move all terms to the left:
1/5(2y+4)-(1/2(y-3))=0
Domain of the equation: 5(2y+4)!=0
y∈R
Domain of the equation: 2(y-3))!=0
y∈R
We calculate fractions
(2yy/(5(2y+4)*2(y-3)))+(-5y2/(5(2y+4)*2(y-3)))=0
We calculate terms in parentheses: +(2yy/(5(2y+4)*2(y-3))), so:
2yy/(5(2y+4)*2(y-3))
We multiply all the terms by the denominator
2yy
Back to the equation:
+(2yy)
We calculate terms in parentheses: +(-5y2/(5(2y+4)*2(y-3))), so:
-5y2/(5(2y+4)*2(y-3))
We multiply all the terms by the denominator
-5y2
We add all the numbers together, and all the variables
-5y^2
Back to the equation:
+(-5y^2)
We get rid of parentheses
-5y^2+2yy=0

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