If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/5(3(x-1)+15)=x
We move all terms to the left:
1/5(3(x-1)+15)-(x)=0
Domain of the equation: 5(3(x-1)+15)!=0We add all the numbers together, and all the variables
x∈R
-1x+1/5(3(x-1)+15)=0
We multiply all the terms by the denominator
-1x*5(3(x-1)+15)+1=0
Wy multiply elements
-5x^2(3+1=0
| 3/8n+5(n-6)=1+7/8n-2 | | 2s=1 | | 7d+9-5d=7d-6 | | 15.4=x−13.9 | | 7x+4=9×- | | -9g=5(-4+2g) | | 3-2(2m+1)=m+17 | | -8b-8=-7b | | 12n=42* | | 7x-3+2x=-3(-x-7) | | -4-6k=10k-8 | | 10+3f=-8-4f+5f | | 11/12x=121/132 | | 3(x+7)+66=180 | | 2(x+2)+112=180 | | a-25=36 | | -3t-8=-2t-1 | | 3x-14=x+40 | | 7=1/6(8x+24) | | 27=8–5x | | 11x-15+5x-13=180° | | -27=8x–5 | | 2-w=6w-5-8w | | 7={1}{6}(8x+24)61 (8x+24) | | -4z+5=z | | 8x(x-1)=〖7x〗^2+4x | | -4x-4=-84+4x | | 4k+8=3k+1 | | 2(2x1)=3x+7 | | 4.5k+5−1.5k=14 | | 4x–7=3(2x+5) | | 4d4-8d3-7d2-11d+6=0 |