1/5(31-x)=1/2x

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Solution for 1/5(31-x)=1/2x equation: 



1/5(31-x)=1/2x

We move all terms to the left:

1/5(31-x)-(1/2x)=0



Domain of the equation: 5(31-x)!=0

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/5(-1x+31)-(+1/2x)=0

We get rid of parentheses

1/5(-1x+31)-1/2x=0

We calculate fractions


2x/(-10x^2+310x)+(-5x(-)/(-10x^2+310x)=0



We calculate terms in parentheses: +(-5x(-)/(-10x^2+310x), so:

-5x(-)/(-10x^2+310x

We add all the numbers together, and all the variables

-5x0/(-10x^2+310x

We multiply all the terms by the denominator


-5x0

We add all the numbers together, and all the variables

-5x

Back to the equation:

+(-5x)



We get rid of parentheses

2x/(-10x^2+310x)-5x=0

We multiply all the terms by the denominator


-5x*(-10x^2+310x)+2x=0

We multiply parentheses

50x^3-1550x^2+2x=0

We do not support expression: x^3

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