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(1/5)*(35*x-(15*y)) = 0
(1/5)*(35*x-15*y) = 0
1/5*(35*x-15*y) = 0
( 1/5 )
1/5 = 0
x belongs to the empty set
( 35*x-15*y )
35*x-15*y = 0 // + -15*y
35*x = -(-15*y) // : 35
x = (-(-15*y))/35
x = (3*y)/7
x = (3*y)/7
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