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n in (-oo:+oo)
(1/5)*(3*n+5) = n/2+10 // - n/2+10
(1/5)*(3*n+5)-(n/2)-10 = 0
1/5*(3*n+5)-n/2-10 = 0
(1/5*2*(3*n+5))/2-n/2+(-10*2)/2 = 0
1/5*2*(3*n+5)-n-10*2 = 0
1/5*n-20+2 = 0
1/5*n-18 = 0
(1/5*n-18)/2 = 0
(1/5*n-18)/2 = 0 // * 2
1/5*n-18 = 0
1/5*n-18 = 0 // + 18
1/5*n = 18 // : 1/5
n = 18/1/5
n = 90
n = 90
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