1/5(3r-4)2/5

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Solution for 1/5(3r-4)2/5 equation: 


r in (-oo:+oo)

((1/5)*(3*r-4)^2)/5 = 0

(1/5*(3*r-4)^2)/5 = 0

( 1/5 )

1/5 = 0

r belongs to the empty set

( 3*r-4 )

3*r-4 = 0 // + 4

3*r = 4 // : 3

r = 4/3

r in { 4/3, 4/3 }

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