1/5(3r-4)=35

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Solution for 1/5(3r-4)=35 equation: 



1/5(3r-4)=35

We move all terms to the left:

1/5(3r-4)-(35)=0



Domain of the equation: 5(3r-4)!=0

r∈R



We multiply all the terms by the denominator


-35*5(3r-4)+1=0

Wy multiply elements

-175r(3+1=0

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