1/5(3t-6)=1/10(t+6)

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Solution for 1/5(3t-6)=1/10(t+6) equation: 



1/5(3t-6)=1/10(t+6)

We move all terms to the left:

1/5(3t-6)-(1/10(t+6))=0



Domain of the equation: 5(3t-6)!=0

t∈R





Domain of the equation: 10(t+6))!=0

t∈R



We calculate fractions


(10tt/(5(3t-6)*10(t+6)))+(-5t3/(5(3t-6)*10(t+6)))=0



We calculate terms in parentheses: +(10tt/(5(3t-6)*10(t+6))), so:

10tt/(5(3t-6)*10(t+6))

We multiply all the terms by the denominator


10tt

Back to the equation:

+(10tt)





We calculate terms in parentheses: +(-5t3/(5(3t-6)*10(t+6))), so:

-5t3/(5(3t-6)*10(t+6))

We multiply all the terms by the denominator


-5t3

We add all the numbers together, and all the variables

-5t^3

We do not support etpression: t^3

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