1/5(3t-9)=(9/5t)-(t+9)/10

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Solution for 1/5(3t-9)=(9/5t)-(t+9)/10 equation: 


t in (-oo:+oo)

(1/5)*(3*t-9) = (9/5)*t-((t+9)/10) // - (9/5)*t-((t+9)/10)

(1/5)*(3*t-9)+(t+9)/10-((9/5)*t) = 0

(1/5)*(3*t-9)+(t+9)/10+(-9/5)*t = 0

1/5*(3*t-9)+(t+9)/10+(-9*t)/5 = 0

(1/5*5*10*(3*t-9))/(5*10)+(5*(t+9))/(5*10)+(-9*10*t)/(5*10) = 0

1/5*5*10*(3*t-9)+5*(t+9)-9*10*t = 0

35*t-90*t-45 = 0

-55*t-45 = 0

(-55*t-45)/(5*10) = 0

(-55*t-45)/(5*10) = 0 // * 5*10

-55*t-45 = 0

-55*t-45 = 0 // + 45

-55*t = 45 // : -55

t = 45/(-55)

t = -9/11

t = -9/11

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