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1/5(3x+4)-x=5-1/3(2x-1)
We move all terms to the left:
1/5(3x+4)-x-(5-1/3(2x-1))=0
Domain of the equation: 5(3x+4)!=0
x∈R
Domain of the equation: 3(2x-1))!=0We add all the numbers together, and all the variables
x∈R
-1x+1/5(3x+4)-(5-1/3(2x-1))=0
We calculate fractions
-1x+(3x2/(5(3x+4)*3(2x-1)))+(-(-5x3)/(5(3x+4)*3(2x-1)))=0
We calculate terms in parentheses: +(3x2/(5(3x+4)*3(2x-1))), so:
3x2/(5(3x+4)*3(2x-1))
We multiply all the terms by the denominator
3x2
We add all the numbers together, and all the variables
3x^2
Back to the equation:
+(3x^2)
We calculate terms in parentheses: +(-(-5x3)/(5(3x+4)*3(2x-1))), so:
-(-5x3)/(5(3x+4)*3(2x-1))
We add all the numbers together, and all the variables
-(-5x^3)/(5(3x+4)*3(2x-1))
We multiply all the terms by the denominator
-(-5x^3)
We do not support expression: x^3
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