1/5(3x+6)=1/10(2x-14)

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Solution for 1/5(3x+6)=1/10(2x-14) equation: 



1/5(3x+6)=1/10(2x-14)

We move all terms to the left:

1/5(3x+6)-(1/10(2x-14))=0



Domain of the equation: 5(3x+6)!=0

x∈R





Domain of the equation: 10(2x-14))!=0

x∈R



We calculate fractions


(10x2/(5(3x+6)*10(2x-14)))+(-5x3/(5(3x+6)*10(2x-14)))=0



We calculate terms in parentheses: +(10x2/(5(3x+6)*10(2x-14))), so:

10x2/(5(3x+6)*10(2x-14))

We multiply all the terms by the denominator


10x2

We add all the numbers together, and all the variables

10x^2

Back to the equation:

+(10x^2)





We calculate terms in parentheses: +(-5x3/(5(3x+6)*10(2x-14))), so:

-5x3/(5(3x+6)*10(2x-14))

We multiply all the terms by the denominator


-5x3

We add all the numbers together, and all the variables

-5x^3

We do not support expression: x^3

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