1/5(3x-1/2)+1/6=x/5+1/2

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Solution for 1/5(3x-1/2)+1/6=x/5+1/2 equation:


x in (-oo:+oo)

(1/5)*(3*x-(1/2))+1/6 = x/5+1/2 // - x/5+1/2

(1/5)*(3*x-(1/2))-(x/5)+1/6-(1/2) = 0

(1/5)*(3*x-1/2)-(x/5)+1/6-1/2 = 0

1/5*(3*x-1/2)-x/5+1/6-1/2 = 0

(1/5*2*5*6*(3*x-1/2))/(2*5*6)+(2*6*(-x))/(2*5*6)+(1*2*5)/(2*5*6)+(-1*5*6)/(2*5*6) = 0

1/5*2*5*6*(3*x-1/2)+2*6*(-x)+1*2*5-1*5*6 = 0

24*x-30-6+10 = 0

24*x-30+4 = 0

24*x-26 = 0

(24*x-26)/(2*5*6) = 0

(24*x-26)/(2*5*6) = 0 // * 2*5*6

24*x-26 = 0

24*x-26 = 0 // + 26

24*x = 26 // : 24

x = 26/24

x = 13/12

x = 13/12

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