1/5(40x+45)-16=-1/4(24x-8)

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Solution for 1/5(40x+45)-16=-1/4(24x-8) equation: 



1/5(40x+45)-16=-1/4(24x-8)

We move all terms to the left:

1/5(40x+45)-16-(-1/4(24x-8))=0



Domain of the equation: 5(40x+45)!=0

x∈R





Domain of the equation: 4(24x-8))!=0

x∈R



We calculate fractions


(4x2/(5(40x+45)*4(24x-8)))+(-(-5x4)/(5(40x+45)*4(24x-8)))-16=0



We calculate terms in parentheses: +(4x2/(5(40x+45)*4(24x-8))), so:

4x2/(5(40x+45)*4(24x-8))

We multiply all the terms by the denominator


4x2

We add all the numbers together, and all the variables

4x^2

Back to the equation:

+(4x^2)





We calculate terms in parentheses: +(-(-5x4)/(5(40x+45)*4(24x-8))), so:

-(-5x4)/(5(40x+45)*4(24x-8))

We add all the numbers together, and all the variables

-(-5x^4)/(5(40x+45)*4(24x-8))

We multiply all the terms by the denominator


-(-5x^4)

We do not support expression: x^4

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