1/5(45x+40)-17=-1/4(36x-16)

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Solution for 1/5(45x+40)-17=-1/4(36x-16) equation: 



1/5(45x+40)-17=-1/4(36x-16)

We move all terms to the left:

1/5(45x+40)-17-(-1/4(36x-16))=0



Domain of the equation: 5(45x+40)!=0

x∈R





Domain of the equation: 4(36x-16))!=0

x∈R



We calculate fractions


(4x3/(5(45x+40)*4(36x-16)))+(-(-5x4)/(5(45x+40)*4(36x-16)))-17=0



We calculate terms in parentheses: +(4x3/(5(45x+40)*4(36x-16))), so:

4x3/(5(45x+40)*4(36x-16))

We multiply all the terms by the denominator


4x3

We add all the numbers together, and all the variables

4x^3

We do not support expression: x^3

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