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1/5(4x+2)-1/2(2x-1)=10
We move all terms to the left:
1/5(4x+2)-1/2(2x-1)-(10)=0
Domain of the equation: 5(4x+2)!=0
x∈R
Domain of the equation: 2(2x-1)!=0We calculate fractions
x∈R
(2x2/(5(4x+2)*2(2x-1))+(-5x4/(5(4x+2)*2(2x-1))-10=0
We can not solve this equation
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