1/5(4x+2)=1/6(x-1)

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Solution for 1/5(4x+2)=1/6(x-1) equation: 



1/5(4x+2)=1/6(x-1)

We move all terms to the left:

1/5(4x+2)-(1/6(x-1))=0



Domain of the equation: 5(4x+2)!=0

x∈R





Domain of the equation: 6(x-1))!=0

x∈R



We calculate fractions


(6xx/(5(4x+2)*6(x-1)))+(-5x4/(5(4x+2)*6(x-1)))=0



We calculate terms in parentheses: +(6xx/(5(4x+2)*6(x-1))), so:

6xx/(5(4x+2)*6(x-1))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)





We calculate terms in parentheses: +(-5x4/(5(4x+2)*6(x-1))), so:

-5x4/(5(4x+2)*6(x-1))

We multiply all the terms by the denominator


-5x4

We add all the numbers together, and all the variables

-5x^4

We do not support expression: x^4

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