1/5(4x-32)=-3/4(12x-8)

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Solution for 1/5(4x-32)=-3/4(12x-8) equation: 



1/5(4x-32)=-3/4(12x-8)

We move all terms to the left:

1/5(4x-32)-(-3/4(12x-8))=0



Domain of the equation: 5(4x-32)!=0

x∈R





Domain of the equation: 4(12x-8))!=0

x∈R



We calculate fractions


(4x1/(5(4x-32)*4(12x-8)))+(-(-15x4)/(5(4x-32)*4(12x-8)))=0



We calculate terms in parentheses: +(4x1/(5(4x-32)*4(12x-8))), so:

4x1/(5(4x-32)*4(12x-8))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-(-15x4)/(5(4x-32)*4(12x-8))), so:

-(-15x4)/(5(4x-32)*4(12x-8))

We add all the numbers together, and all the variables

-(-15x^4)/(5(4x-32)*4(12x-8))

We multiply all the terms by the denominator


-(-15x^4)

We do not support expression: x^4

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