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(1/5)*(5*x+10) = 2*((1/2)*x+1) // - 2*((1/2)*x+1)
(1/5)*(5*x+10)-(2*((1/2)*x+1)) = 0
(1/5)*(5*x+10)-2*((1/2)*x+1) = 0
1/5*(5*x+10)-2*(1/2*x+1) = 0
1/5*(5*x+10)-2*(1/2*x+1) = 0
0 = 0
0 = 0
x belongs to the empty set
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