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1/5(5x+10)=2/7(14x-49)
We move all terms to the left:
1/5(5x+10)-(2/7(14x-49))=0
Domain of the equation: 5(5x+10)!=0
x∈R
Domain of the equation: 7(14x-49))!=0We calculate fractions
x∈R
(7x1/(5(5x+10)*7(14x-49)))+(-10x5/(5(5x+10)*7(14x-49)))=0
We calculate terms in parentheses: +(7x1/(5(5x+10)*7(14x-49))), so:
7x1/(5(5x+10)*7(14x-49))
We multiply all the terms by the denominator
7x1
We add all the numbers together, and all the variables
7x
Back to the equation:
+(7x)
We calculate terms in parentheses: +(-10x5/(5(5x+10)*7(14x-49))), so:
-10x5/(5(5x+10)*7(14x-49))
We multiply all the terms by the denominator
-10x5
We add all the numbers together, and all the variables
-10x^5
We do not support expression: x^5
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