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1/5(5x+10)=31+4x
We move all terms to the left:
1/5(5x+10)-(31+4x)=0
Domain of the equation: 5(5x+10)!=0We add all the numbers together, and all the variables
x∈R
1/5(5x+10)-(4x+31)=0
We get rid of parentheses
1/5(5x+10)-4x-31=0
We multiply all the terms by the denominator
-4x*5(5x+10)-31*5(5x+10)+1=0
Wy multiply elements
-20x^2(5-155x(5+1=0
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